Defind Count Method

Points: 40 (partial)

Time limit: 1.0s

Memory limit: 256M

Authors:

scu09156238, scu09156146

Problem type

Allowed languages

Java 19, Java 8

題目說明

請寫出Count方法，計算陣列中的目標數有幾個

import java.util.Scanner;

public class defindCountMethod {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner input = new Scanner(System.in);
        int len = input.nextInt();
        int[] nums = new int[len];
        for (int i = 0; i < len; i++) {
            nums[i] = input.nextInt();
        }
        int target = input.nextInt();
        input.close();

        System.out.print(target + " has " + Count(nums, target));   // 呼叫副程式
    }

    // 定義Count方法


}

輸入限制：0~9的整數

輸入

陣列長度
陣列資料
目標數

輸出

(目標數) has (幾個)

測試資料1 輸入

6
2 5 3 1 0 4
0

測試資料1 輸出

0 has 1

// 0在陣列裡出現1次

Comments

scu09156146 commented on April 12, 2024, 5:25 p.m.

題解

import java.util.Scanner;

public class MyProgram {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner input = new Scanner(System.in);
        int len = input.nextInt();
        int[] nums = new int[len];
        for (int i = 0; i < len; i++) {
            nums[i] = input.nextInt();
        }
        int target = input.nextInt();
        input.close();

        System.out.print(target + " has " + Count(nums, target)); // 呼叫副程式，印出回傳值
    }

    // 定義Count方法
    public static int Count(int[] array, int target) {
        int count = 0;
        for (int i = 0; i < array.length; i++) {
            if (array[i] == target)
                count++;
        }
        return count;
    }

}