a plus aa plus aaa (simple version)

Submit solution
Points: 10 (partial)
Time limit: 5.0s
Memory limit: 256M
Author:
ctwen
Problem type
Allowed languages
Java 19, Java 8

題目說明

輸入一個正整數(a)

求s=a+aa+aaa的值。假設a=2，則輸出結果的形式如：2+22+222=246；

輸入限制: a為介於0~9之間的正整數

輸入

正整數a

輸出

a+aa+aaa= (如上形式所示)

sample input1

1

sample output1

1+11+111=123

sample input2

3

sample output2

3+33+333=369

Comments


  • 0
    scu12115149  commented on Oct. 8, 2025, 12:23 a.m.

    import java.util.Scanner; public class HW_3_2 {

    public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner sc = new Scanner(System.in);

    System.out.println("正整數a:");
    int a=sc.nextInt();



    if (a <= 0 ){
    System.out.println("輸入錯誤");}

    if (a >= 9 ){
        System.out.println("輸入錯誤 ");}


    int s=a*(1+11+111);

    System.out.println(a+"+"+(a*10+a)+"+"+(a*100+a*10+a)+"="+s);