Sum All

Points: 40 (partial)

Time limit: 1.0s

Memory limit: 256M

Authors:

scu09156238, scu09156146

Problem types

Allowed languages

Java 19

題目說明

給一陣列長度，再輸入陣列的值

輸入限制：整數

vvv使用以下程式碼作答vvv

import java.util.Scanner;

public class SumAll {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int[] array = new int[n];
        for (int i = 0; i < n; i++) {
            array[i] = in.nextInt();
        }
        in.close();

        // 傳陣列、長度到副程式，做加總
        System.out.print(sum(array, n));
    }

    public static int sum(int[] array, int n) {
        // 要執行的程式碼
        // 記得return
    }

}

輸入

1個整數

輸出

正整數

測試資料0 輸入

7
2 3 6 9 8 7 0

測試資料0 輸出

測試資料1 輸入

1
3

測試資料1 輸出

Comments

scu09156146 commented on April 12, 2024, 2:02 p.m.

題解

import java.util.Scanner;

public class SumAll {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int[] array = new int[n];
        for (int i = 0; i < n; i++) {
            array[i] = in.nextInt();
        }
        in.close();

        // 傳陣列、長度到副程式，做加總
        System.out.print(sum(array, n));
    }

    public static int sum(int[] array, int n) {
        int sum = 0;
        for (int i = 0; i < n; i++) {
            sum += array[i];
        }
        return sum;
    }

}